A square filamentary loop of wire is 25 cm on a side and has a resistance of 125 S2 per meter length. The loop lies in the z 0 plane with its corners at (0, 0, 0), (0.25, 0, 0), (0.25, 0.25, 0), and (0, 0.25, 0) at t 0. The loop is moving with a velocity vy 50 m/s in the field B. 38 cos(1.5 x 10st 0.5x) AuT. Develop a function of time that expresses the ohmic power being delivered to the loop

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group

more i think

hope this !