Suppose you had a box of cards with 6 red suited cards and 4 black suited cards. Further suppose that the first card drawn was red and was not replaced, and the second card drawn was black. The probability of drawing the first (red) card is and the probability of drawing the second (black) card is .

Step-by-step explanation:

Given that you had a box of cards with 6 red suited cards and 4 black suited cards. Further suppose that the first card drawn was red and was not replaced, and the second card drawn was black

Since without replacement, we find I card red will not be replaced.

So for drawing second card, available cards would be 5 red and 4 black.

The probability of drawing the first (red) card is ______

= no of red cards/total cards

=

The probability of drawing the second (black) card is ______.

= no of black cards available/total cards avaialble

=

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: