Given parallelogram PARK.
Prove graphically and algebraically that a clockwise rotation of 270° about the origin has an equivalent
counterclockwise rotation. In your final answer, name the equivalent counterclockwise rotation and show all of your
work. On your graph, label the following:
1. parallelogram PARK and the coordinates of all four of its vertices
2. parallelogram P'A'R'K' and the coordinates of all four of its vertices
3. center of rotation and its coordinate
4. the invisible circle of rotation, its radius and the length of the radius
5. use arrows to show the clockwise movement of the parallelogram

dunno

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

∠cbe and ∠deb are same-side interior angles.

i took the test

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.