Mathematics, 07.03.2020 03:41, batista68
Suppose that over the long run a manufacturing process produces 1% defective items. Use the Poisson approximation to the binomial distribution to calculate the probability of getting two or more defectives in a sample of 200 items.
Answers: 2
![P(x\geq 2)=1-{P(x=0)+P(x=1)+P(x=2)]](/tpl/images/0537/4512/e71e5.png)
![P(x\geq 2)=1-[{e^{-2} \frac{2^{0} }{0!} } +e^{-2} \frac{2^{1} }{1!} +e^{-2} \frac{2^{2} }{2!} ]](/tpl/images/0537/4512/6991c.png)
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Suppose that over the long run a manufacturing process produces 1% defective items. Use the Poisson...
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