Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 0.14, 0.15, 0.16, 0.17, 0.18. Determine the mean and variance of the coating thickness for this process. Round your answers to four decimal places (e. g. 98.7654).

We can calculate the sample variance with the following formula:

And replacing we got:

And the deviation is given by this:

If we want to find the population deviation we just need to use this formula:

And replacing we got:

And the population deviation would be:

Step-by-step explanation:

For this case we have the following values:

0.14, 0.15, 0.16, 0.17, 0.18.

We can calculate the mean with the following formula:

And replacing we got:

We can calculate the sample variance with the following formula:

And replacing we got:

And the deviation is given by this:

If we want to find the population deviation we just need to use this formula:

And replacing we got:

And the population deviation would be:

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.