Distance Between Two Ships Two ships leave the same port at noon. Ship A sails north at 14 mph, and ship B sails east at 18 mph. How fast is the distance between them changing at 1 p. m.? (Round your answer to one decimal place.)

c = 22.8 miles/hr

Step-by-step explanation:

The ship A sails north at the rate of 14 mile per hour , it represent the opposite side of a triangle. Ship B start at the same point and move east at the rate of 18 miles per hour, it represent the adjacent side.

The other rate telling you how fast the distance between them are changing can be computed using the Pythagorean theorem, since the change in time is 1 hour. From 12 noon to 1 pm.

c = ?

a = 14

b = 18

c² = a² + b²

c² = 14² + 18²

c² = 196  + 324

c² = 520

c = √520

c = 22.803508502

c = 22.8 miles/hr

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

answer: 7

step-by-step explanation: