For each of the following integrals find an appropriate trigonometric substitution of the form x=f(t) to simplify the integral. a)x= ∫(6x2−7)3/2dx b) x= ∫x26x2+5‾‾‾‾‾‾‾√dx c) x= ∫x8x2−48x+67‾‾‾‾‾‾‾‾‾‾‾‾‾‾√dx d) x= ∫x−70−3x2+30x‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√dx

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80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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