A particular fruit's weights are normally distributed, with a mean of 610 grams and a standard deviation of 31 grams. If you pick one fruit at random, what is the probability that it will weigh between 589 grams and 602 grams 0 Incorrect

0.14918.

Step-by-step explanation:

We have been given that a particular fruit's weights are normally distributed, with a mean of 610 grams and a standard deviation of 31 grams. We are asked to find the probability that a fruit  will weigh between 589 grams and 602 grams.

First of all, we will find z-score corresponding to 589 and 602 using z-score formula.

Now, we need to find .

Using property , we will get:

From normal distribution table, we will get:

Therefore, the probability that one fruit will weight between 589 grams and 602 grams is 0.14918.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers