Try to visualize the set of all points 1x, y, z2 in a coordinate space that are equidistant from the points P10, 0, 02 and Q10, 3, 02. Use the Distance Formula to find an equation for this surface, and observe that it is a plane.

Y plane at y=3/2 contains all the points which will be equidistant from both points P and Q.

Step-by-step explanation:

As the complete question is not readable, the question is found online and is attached herewith.

By the distance formula, as the point R with coordinates x,y,z is equidistant from P and Q thus

So the y plane at y=3/2 contains all the points which will be equidistant from both points P and Q.

my answer is$ 12

step-by-step explanation:

because 15 -2=12

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?