Let the test statistic Z have a standard normal distribution when H0 is true. Give the P-value for each of the following situations. (Round your answers to four decimal places.)

(a) Ha: μ > μ0, z = 1.73 P-value =
(b) Ha: μ < μ0, z = −2.68 P-value =
(c) Ha: μ ≠ μ0, z = 2.76 or z = −2.76

(a) P-value = 0.0418

(b) P-value = 0.0037

(c) P-value = 0.0058

Step-by-step explanation:

(a) The test is a right one-tailed test because the alternate hypothesis is expressed using greater than.

Test statistic z = 1.73. Cumulative area of the test statistic = 0.9582

P-value = 1 - 0.9582 = 0.0418

(b) The test is a left one-tailed test because the alternate hypothesis is expressed using less than.

Test statistic z = -2.68

Cumulative area of the test statistic = 0.9963

P-value = 1 - 0.9963 = 0.0037

(c) The test is a two-tailed test because the alternate hypothesis is expressed using not equal to.

Test statistic z = + or - 2.76

Cumulative area of the test statistic = 0.9971

P-value = 2(1 - 0.9971) = 2×0.0029 = 0.0058

take the top number and divide it by a the bottom number

step-by-step explanation:

1/2 1 divied by 2 = .5

69

step-by-step explanation: