Consider a binomial experiment with n = 20 and p = .70.

a. Compute f(12) (to 4 decimals).

b. Compute f(16) (to 4 decimals).

c. Compute P(x 16) (to 4 decimals).

d. Compute P(x 15) (to 4 decimals).

e. Compute E(x).

f. Compute Var(x) (to 1 decimal) and (to 2 decimals).

Var(x)

Var(x)=npq=4.2

Step-by-step explanation:

Given that X is binomial n=20: p=0.70

a) Compute f(12) (to 4 decimals).

=

b) Compute f(16) (to 4 decimals).

=

c) Compute P(x <16) (to 4 decimals).

=

d) Compute P(x <15) (to 4 decimals).

=

e) Compute E(x). =np = 14

f) Compute Var(x) (to 1 decimal) and (to 2 decimals).

Var(x)=npq=4.2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204