(2x+5) ^3 in standard form

8x^3+60x^2+150x+125

Step-by-step explanation:

(2x+5)^3=(2x+5)(2x+5)^2 =

(2x+5)(4x^2 +2*2x*5+25)=

(2x+5)(4x^2 +20x+25)=

(2x*4x^2 +2x*20x+2x*25+5*4x^2+5*20x+5*25)=

8x^3+40x^2+50x+20x^2 +100x+125=

8x^3+60x^2+150x+125

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: