M∠QPS=47 ∘ m, angle, Q, P, S, equals, 47, degrees \qquad m \angle RPS = 3x - 38^\circm∠RPS=3x−38 ∘ m, angle, R, P, S, equals, 3, x, minus, 38, degrees \qquad m \angle QPR = 7x - 95^\circm∠QPR=7x−95 ∘

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: