The vertex of a parabolic function is located at (5,−4). One of its zeros (x-intercepts) occurs at x = 7. Where will its other zero (x-intercept) be located?

The answer to the question is

Its other zero (x-intercept) will be located at x = -5

Step-by-step explanation:

To solve the question, we note that a parabolic function is of the form

ax² + bx +c = 0

Therefore we have the vertex occurring at the extremum  where the slope = 0

or dy/dx =2a+b = 0 also the x intercept occurs at x = 7, therefore when

ax² + bx +c = 0, x = 7 which is one of the solution

when x = 5, y = -4

That is a*25 +5*b + c = -4 also

49*a + 7*b + c = 0

2*a + b = 0

Solving the system of equations we get

a = 0.2, b = -0.4 and c = -7

That is 0.2x² -0.4x -7 = 0 which gives

(x+5)(x-7)×0.2 = 0

Therefore the x intercepts are 7 and -5

the second intercept will be located at x = -5

answer: the value of x is 7cm

step-by-step explanation:

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq