The perimeter of a square must be greater than 148 inches but less than 196 inches. Find the range of possible side lengths that satisfy these conditions. (Hint: The perimeter of a square is given by P=4s, where s represents the length of a side).

The possible values of s are the values between 37 and 49(Excluding 37 and 49)

Step-by-step explanation:

If the perimeter of the square must be greater than 148 inches but less than 196 inches.

And Perimeter of a Square=4s

We intend to find the values of s such that:

148<4s<196

Solving the first part

148<4s

148/4<4s/4

37<s

Also

4s<196

s<196/4

s<49

Therefore:

37<s<49

The possible values of s are the values between 37 and 49(Excluding 37 and 49)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3