A certain lottery has 38 numbers. In how many different ways can 4 of the numbers be selected? (Assume that order of selection is not important.)

There are 73815 ways of selecting 4 of the lottery numbers.

Step-by-step explanation:

The total amount of ways to pick 4 numbers from a set of 38 ignoring the order is given by the combinatorial number of 38 with 4, denoted by , which is

Therefore, there are 73815 ways of picking 4 of the numbers.

We conclude that have 73815 a different ways.

Step-by-step explanation:

We know that a certain lottery has 38 numbers. We assume that order of selection is not important. We calculate  how many different ways can 4 of the numbers be selected.

So out of 38 numbers we choose 4 numbers. We get:

We conclude that have 73815 a different ways.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!