What is the center of a circle whose equation is x2 + y2 – 12x - 2y + 12 = 0?
(-12, -2)
O (-6, -1)
(6, 1)
O (12, 2)

Solution:

Given equation of circle is:

Move the constant to other side

Group the equation

Add 36 and 1 from both sides

Which is simplified as:

--------- eqn 1

The equation of circle is given as:

Where, r is radius and (h, k) is center

Compare eqn 1 with above general equation

(h, k) = (6, 1)

Thus the center of a circle is (6, 1)

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: