5. Solve the following equation for A : 2A/3 = 8 + 4A
A.-2.4
B. 2.4
C. 1.3
D. -1.3
E. O

A

Step-by-step explanation:

Given

= 8 + 4A

Multiply through by 3 to clear the fraction

2A = 24 + 12A ( subtract 12A from both sides )

- 10A = 24 ( divide both sides by - 10 )

A = - 2.4 → A

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."