A rectangle has an area of 56 square inches and a perimeter of 36 inches.
Complete the table and write a system of equations to represent the length and width of the rectangle.

Table #1:

Length (L) | Width (W) | Area (56)

Table #2:

Length (2L) | Width (2W) | Perimeter (36)

Equation #1: L · W = 56

Equation #2: 2L + 2W = 36

Step-by-step explanation:

The following are the formulas used to find the area and the perimeter of a rectangle:

Area = L · W

Perimeter = L + L + W + W

If you group common variables, you can simplify the formula used to find the perimeter down to:

Perimeter = L + L + W + W

Perimeter = 2L + 2W (Since you're adding 2 of each)

Using these formulas, we can insert our values into them. We know that the rectangle has an area of 56 square inches meaning:

L · W = 56

We know that the rectangle has a perimeter of 36 inches meaning:

2L + 2W = 36

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step-by-step explanation:

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(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240