Write an equation in slope intercept form for the line that has a slope of 12 and passes through the point (3,20)

y= 12x-16

Step-by-step explanation:

Given that you have a slope of 12 and a point of (3, 20), you are most obligated to using the Slope-Intercept form, or y=mx+b.

What this allows you to find is the y-intercept if your line has one. You take your point, (3,20), and you insert the values at the appropriate places. You should now have 20=12(3)+b. You will then solve for b by multiplying 12 and 3 to get 36 and subtract that from both sides of the equal sign. You should have 20-36=b. 20-36 is -16, which is your y-intercept.

Now you know all your needed values, you would write the Slope-Intercept form without the values for y and x, to represent your equation.

Since 12 is your slope, it will be 'm' and -16 will be 'b'.

You will end with y = 12x - 16.

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