A picture frame holds a 4-in. by 6-in. photograph. the frame adds a border x inches wide around the three sides of the photo. on the fourth side the frame forms a border that is 3x - 0.5 in. wide. the combined area of the photograph and the frame is 80.5 in^2. write a quadratic equation for the combined area. Then use the quadratic equation formula to find x

1. The quadratic equation is 3x² +17.5x - 58.5 = 0

2. The values of x are 2.38 and -8.21, but we only take 2.38 for our problem.

3. The dimensions of the combined area are approximately 6.38 inches and 12.64 inches.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Photograph dimensions = 4 inches * 6 inches

Frame dimensions = x inches * 3x - 0.5 inches

Area of the combined area of the photograph and the frame = 80.5 inches²

2. Write a quadratic equation for the combined area. Then use the quadratic equation formula to find x.

One side of the combined area of the photograph and the frame = 4 + x inches

Second side of the combined area of the photograph and the frame = 6 + 3x - 0.5 inches

Now, we can write the quadratic equation this way:

Combined area of the photograph and the frame = One side * Second side, replacing with the values we know:

80.5 = (4 + x) * (6 + 3x - 0.5)

80.5 =  (4 + x) * (5.5 + 3x)

80.5 = 22 + 5.5x + 12x + 3x²

3x² +17.5x - 58.5 = 0

Using the quadratic formula, where, a = 3, b = 17.5 and c = - 58.5, we have:

x = (-b +/- √b² - 4ac)/2a

x = (-17.5 +/- √17.5² - 4 * 3 * -58.5) 2 * 3

x = (-17.5 +/- √306.25 + 702)/6

x = (-17.5 +/- √1,008.25)/6

x = (-17.5 +/- 31.75)/6

x₁ = 14.25/6 = 2.38

x₂ = -49.25/6 = -8.21

We took the value of x₁ because x₂ is negative and we can't have a negative value for the length or the width, therefore:

80.5 = (4 + x) * (5.5 + 3x)

Replacing x, we have:

80.5 = (4 + 2.38) * (5.5 + 3 * 2.38)

80.5 = 6.38 * 12.64

80.5 ≅ 6.38 * 12.64

-6 is the correct option from the above given options

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it