Mathematics, 04.03.2020 02:51, farihasy6508
Consider a three-year loan (so we'll assume the numbers 1 through 36) for $5,000 with interest at 10% per year. Using standard amortization, the monthly payment is $161.33. In this example, we will not worry about exact or ordinary interest because the total interest to be paid is $808.13.
After the fifth month, the borrower decides to prepay the whole loan. Under a standard amortization plan the borrower would have paid $198.28 in cumulative interest. However, using the Rule of 78 a lender would calculate the fraction of the total interest based on two series:
{(n+35)+(n+34)+(n+33)+(n+32)+(n+31) }
{(n)+(n+1)+...+(n+35)}
Answers: 2
Mathematics, 21.06.2019 13:40, kemzzoo7206
Desmond wants to sell his car that he paid $8,000 for 2 years ago. the car depreciated, or decreased in value, at a constant rate each month over a 2-year period. if x represents the monthly depreciation amount, which expression shows how much desmond can sell his car for today? 8,000 + 24x 8,000 β 24x 8,000 + 2x 8,000 β 2x
Answers: 1
Mathematics, 21.06.2019 16:00, ctyrector
Asap for seven months an ice creams vendor collects data showing the number of cones sold a day (c) and the degrees above 70 degrees f the vendor finds that there is a positive linear association between c and t that is the best modeled by this equation c=3.7t+98 which statement is true? the model predicts that the average number of cones sold in a day is 3.7 the model predicts that the average number of cones sold i a day is 98 a model predicts that for each additional degree that the high temperature is above 70 degres f the total of number of cones sold increases by 3.7 the model predicts for each additional degree that the high temperature is above 70 degrees f the total number of cones sold increasingly by 98
Answers: 3
Consider a three-year loan (so we'll assume the numbers 1 through 36) for $5,000 with interest at 10...
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