In the 2009 General Social Survey, respondents were asked if they favored or opposed death penalty for people convicted of murder. The 95% confidence interval for the population proportion who were in favor (say, p) was (0.65, 0.69). For the above data, the 99% confidence interval for the true population proportion of respondents who were opposed to the death penalty would be narrower than the one your derived above

The calculated 99% confidence interval is wider than the 95% confidence interval.      

Step-by-step explanation:

We are given the following in the question:

95% confidence interval for the population proportion

(0.65, 0.69)

Let be the sample proportion

Confidence interval:

Let x be the standard error, then, we can write

Solving the two equations, we get,

99% Confidence interval:

Putting values, we get,

Thus, the calculated 99% confidence interval is wider than the 95% confidence interval .

what is the original number? you forgot to add it.

sorry i need the points

step-by-step explanation:

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