What are the zeros of f(x) = x2 + 2x - 80?
-20 and 4
®
-4 and 20
-10 and 8
-8 and 10

The zeros are 8 and -10, all u have to do is substitute x for those values, factor it, or graph it.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer is b i just did that

step-by-step explanation: