(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

The coordinates of the vertices of quadrilateral ABCD are (7, -7), (4, -10), (1.5, -2.5), and (6, -3), respectively.

If quadrilateral ABCD is rotated 180° counterclockwise about the origin, what are the coordinates of D’?

A. (6, 3)
B. (3, -6)
C. (-6, 3)
D. (-3, 6)

C. Coordinates of D' (-6,3)

Step-by-step explanation:

When any figure is rotated 180° in the counterclockwise direction, then the coordinates of the vertices is changed into its opposite sign.

(x, y) → (-x, -y)

The coordinates of the vertices of quadrilateral ABCD is changed when it is rotated 180 degrees counterclockwise about the origin as,

A (7,-7) → A'(-7,7)

B (4,-10) → B' (-4,10)

C (1.5, -2.5) → C' (-1.5, 2.5)

D (6, -3) → D'(-6,3)

So the coordinates of D' will be (-6,3)

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4