His season, Lisa's lacrosse team has won $\frac 23$ of their home games (games played at Lisa's school), but just $\frac 25$ of their away games (games played at other schools). In total, Lisa's team has won $26$ games out of $49$ games they have played. How many home games has Lisa's team played?

Solution:

Let "h" be the number of home games

Let "a" be the number of away games

The total number of games is 49

Therefore,

h + a = 49 ---------- eqn 1

They won 2/3 of the home games and 2/5 of the away games

There were 26 games won

Thus we get,

10h + 6a = 390 --------- eqn 2

Multiply eqn 1 by 6

6h + 6a = 294 ----------- eqn 3

Subtract eqn 3 from eqn 2

10h + 6a = 390

6h + 6a = 294

( - ) ------------------

4h = 96

h = 24

Thus 24 home games were played

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

the answer is simply just 6n add the two together as they have an n