You collect 100 samples from a large butterfly population. Fifty specimens are dark brown, 20 are speckled, and 30 are white. Coloration in this species of butterfly is controlled by one gene locus: BB individuals are brown, Bb are speckled, and bb are white. What are the allele frequencies for the coloration gene in this population

Total Allele: 100

BB = 100 ;  Bb = 40 ;  bb = 60

Step-by-step explanation:

There are two allele in each gene. Since we have 100 samples of butterfly genes, the total number of allele are 100 x 2 = 200.

For each species:

Dark Brown (BB) → 50 x 2 = 100 allele

Speckled (Bb) → 20 x 2 = 40 allele

White (bb) → 30 x 2 = 60 allele

So, if we let be the frequency of the B allele and be the frequency of the b alleles, then:

d

gimmee one of those gold crowns!

~coco