Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D = {(x, y) | 1 ≤ x ≤ 9, 1 ≤ y ≤ 4}; rho(x, y) = ky2

Step-by-step explanation:

Let's begin with the mass definition in terms of density.

Now, we know the limits of the integrals of x and y, and also know that ρ = ky², so we will have:

Let's solve this integral:

So the mass will be:

Now we need to find the x-coordinate of the center of mass.

Now we need to find the y-coordinate of the center of mass.

Therefore the center of mass is:

I hope it helps you!

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{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1