7 people show up to apply for jobs as cashiers at a discount store. Among 7 applicants, four are females. What is the probability that the first three lined up in the interview are all females if the order is chosen at random?

11.43% probability that the first three lined up in the interview are all females if the order is chosen at random

Step-by-step explanation:

Initially, there are 7 applicants, 4 of which are female. So the probability of the first person lined up in the interview being a female is 4/7.

Now we suppose that a female has been chosen, which means that there are 6 applicants, 3 of which are female. So the probability of the second person lined up in the interview being a female is 3/6.

We suppose that the second choice was also a female. Now there are 5 applicants, 2 of which are female. So the probability of the third person lined up in the interview being a female is 2/5.

What is the probability that the first three lined up in the interview are all females if the order is chosen at random?

11.43% probability that the first three lined up in the interview are all females if the order is chosen at random

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer