![\therefore A^{T}=\frac{2}{3} \left[\begin{array}{cc}-4&8\\-5&4\\8&-8\end{array}\right]](/tpl/images/0530/8074/e9da9.png)
![A=\frac{2}{3} \left[\begin{array}{ccc}-4&-5&8\\8&4&-8\end{array}\right]](/tpl/images/0530/8074/65f10.png)
![=\left[\begin{array}{ccc}\frac{2}{3} .(-4)&\frac{2}{3}(-5)&\frac{2}{3}8\\ \\ \frac{2}{3}.8&\frac{2}{3}.4&\frac{2}{3}.(-8)\end{array}\right]](/tpl/images/0530/8074/0fb96.png)
![=\left[\begin{array}{ccc}\frac{-8}{3} &\frac{-10}{3}&\frac{16}{3}\\\ \\ \frac{16}{3}&\frac{8}{3}&\frac{-16}{3}\end{array}\right]](/tpl/images/0530/8074/ac7bb.png)
![A^{T}=\left[\begin{array}{cc}\frac{-8}{3} &\frac{16}{3}\\\ \\ \frac{-10}{3}&\frac{8}{3}\\ \\ \frac{16}{3}&\frac{-16}{3}\end{array}\right]](/tpl/images/0530/8074/99ec4.png)
![=\frac{2}{3} \left[\begin{array}{cc}-4&8\\-5&4\\8&-8\end{array}\right]](/tpl/images/0530/8074/a5fc1.png)
Find the transpose of the matrix A.
Aequals=left bracket Start 2 By 3 Matrix 1st Row 1st...
Mathematics, 02.03.2020 21:47, sweetyus06
Find the transpose of the matrix A.
Aequals=left bracket Start 2 By 3 Matrix 1st Row 1st Column negative 4 2nd Column negative 5 3rd Column 8 2nd Row 1st Column 8 2nd Column 4 3rd Column negative 8 EndMatrix right bracket
−4 −5 8
8 4 −8
Fill in the matrix with entries of the transpose.
left bracket Start 2 By 3 Matrix 1st Row 1st Column negative 4 2nd Column negative 5 3rd Column 8 2nd Row 1st Column 8 2nd Column 4 3rd Column negative 8 EndMatrix right bracket Superscript Upper T
−4 −5 8
8 4 −8
Tequals=left bracket Start 3 By 2 Matrix 1st Row 1st Column nothing 2nd Column nothing 2nd Row 1st Column nothing 2nd Column nothing 3rd Row 1st Column nothing 2nd Column nothing EndMatrix right bracket
Answers: 3
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