Amodel jet is fired up in the air from a 16-foot platform with an initial upward velocity of 52 feet per second. the height of the jet above ground after t seconds is given by the equation y=-16t^+52t+16 where h is the height of the jet in feet and t is the time in seconds since it is launched. what is the maximum height the jet reaches, to the nearest foot?

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation: