Find the sixth term of the
geometric sequence, given the
first term and common ratio.
aq=100 and r=2

The sixth term of the geometric sequence is 3,200.

Step-by-step explanation: A geometric sequence or progression is a sequence in which each successive term is determined by multiplying each previous term by a number that doesn’t change in value throughout the sequence. This number is called the “common ratio” or simply R. In this question we have been given the first term which is A, (100) and we have also been given the common ratio which is R (2). We can use this bit of information to find any term (nth term) of the sequence. The nth term of a geometric progression is given as;

Nth term = AR^ n-1

{This reads, A times R raised to the power of n minus one}

Therefore to calculate the 6th term,

6th = 100 x 2^6-1

6th = 100 x 2^5

6th = 100 x 32

6th = 3200

Therefore the 6th term of the geometric sequence is 3,200.

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this