Suppose that 40% of all families in your city have a dog, and you want to create a simulation to predict the probability that it will take at least 4 random picks from the population to find one family with a dog.

Choose all that correctly describe the use of random digits as a simulation to predict the probability.

Use ten digits ( 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 ), and let 40% of the them represent families with dogs.

Let the digits 0, 1, 2, 3 represent families with dogs, and (4, 5, 6, 7, 8, 9) represent families without dogs.

Find the probability that a 0, 1, 2, or 3 is not generated within the first four random picks.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation:

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.