Solve for x
Logx-log(x+13)=1

Step by step explanation please

Step-by-step explanation:

Applying logarithm rule

Log A - Log B= Log(A/B). Division rule

Now, Logx-log(x+13)=1

Log(x/(x+13))=1

Assume that the log is a natural log whose base is 10.

Then apply logarithm law

Log10 base 10=1

Comparing this to Log(x/(x+13))=1

This implies that

x/(x+13)=10

x=10(x+13)

x=10x+130

x-10x=130

-9x=130

x=130/-9

x=-14.444

21/58.

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