A ball is dropped from the ground. T represents the time in seconds. To find the time you can you the equation Y= -16t^2 +44t. How long is the ball in the air

2.75 seconds.

Step-by-step explanation:

We have been given that a ball is dropped from the ground. T represents the time in seconds.

To find the time when the ball was in air, we will equate height of ball with 0 and solve for t.  

Upon dividing both sides by 4, we will get:

Since our given function is a downward opening parabola, so ball will be in air between both t-intercepts.

Since the ball touches the ground at 2.75 seconds, therefore, the ball would be in air for approximately 2.75 seconds.

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b