An Olympic archer is able to hit the bull’s-eye 80% of the time. Assume each shot is independent of the others. If she shoots 6 arrows, what’s the probability of each of the following results?

a). 0.032

b). 0.999936

c). 0.00768

d). 0.24576

e). 0.9011

f). 0.3446

Step-by-step explanation:

The given question is incomplete; here is the complete question.

An Olympic archer is able to hit the bull’s-eye 80% of the time. Assume each shot is independent of the others. If she shoots 6 arrows, what’s the probability of each of the following results? a) Her first bull’s-eye comes on the third arrow. b) She misses the bull’s-eye at least once. c) Her first bull’s-eye comes on the fourth or fifth arrow. d) She gets exactly 4 bull’s-eyes. e) She gets at least 4 bull’s-eyes. f) She gets at most 4 bull’s-eyes

a). If archer  shots her first bull's-eye on the third arrow.

Since probability to hit the bull's eye = 80% or 0.80

and probability to miss the bull's eye = 20% or 0.20

So P(miss miss hit) = (0.2)(0.2)(0.8) = 0.032

b). She misses the bull's-eye at least one out of 6 arrows.

So, P(misses at least once) = 1 - P(misses all)

=

=

=

= 0.999936

c). P(4th or 5th) =

= 0.0064 + 0.00128

= 0.00768

d). For exactly 4 hits,

From the binomial distribution formula,

Binomial probability =

P(exactly 4 hits) =

P(exactly 4 hits) = 0.2458

e). She gets at least 4 bull's eyes.

P(x ≥ 4) =

P(x ≥ 4) = 0.9011

f). She gets at most 4 bull's eyes.

P(at most 4 bull's eyes) == 0.3446

the circle one

then say something, tell them they won’t respect you if you don’t even have respect for your self sweetheart you need to lay it on them, all of it : )