Help with this one, please

At x = 3 the exponential function h(x) begin to exceed the linear function f(x).

Solution:

Given data:

To find at what value of x in h(x) begin to exceed the linear function f(x).

Substitute x = 1 in f(x) and h(x).

27 > 5

f(x) is not exceed h(x), so proceed further.

Substitute x = 2 in f(x) and h(x).

29 > 25

f(x) is not exceed h(x), so proceed further.

Substitute x = 3 in f(x) and h(x).

31 < 125

f(x) is exceed h(x), the process stops here.

Here the value of x is 3.

Hence at x = 3 the exponential function h(x) begin to exceed the linear function f(x).

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.