Mathematics, 29.02.2020 00:29, davidaagurto

Find the area under the standard normal distribution curve for the following intervals. a. Between z = 0 and z = 2.0 b. To the right of z = 1.5 c. To the left of z = −1.75 d. Between z = −2.78 and z = 1.66

Answers: 2

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answered: jasminali7956

a) P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

b) P(Z1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z1.5) =1-P(Z

c) P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

d) P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

We want this probability:

P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

Part b

For this case we want this probability:

P(Z1.5)

And we can use the complement rule and we have:

P(Z1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z1.5) =1-P(Z

Part c

We want this probability:

P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

Part d

We want this probability:

P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

answered: Guest

46 dollars is the answer.

step-by-step explanation:

6*6 = 36, 36+10=46

answered: Guest

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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Find the area under the standard normal distribution curve for the following intervals. a. Between z...