Identify the oblique asymptote of f(x) = quantity 3 x squared plus 2x minus 5 over quantity x minus 4 .

y = 0
y = 3x − 10
y = 3x + 14
No oblique asymptote

Step-by-step explanation:

Answer is C

We need to find oblique asymtotes of f(x).

Oblique asymtotes form when degree of numerator is greater than denominator.

First we find the degree of numerator and denominator for f(x)

Degree of f(x) at numerator = 2

Degree of f(x) at denominator = 1

So, one oblique asymtote form.

First we divide  by

Quoetient of the above division would be oblique asymtote.

First we find the degree of numerator and denominator for f(x)

Degree of f(x) at numerator = 2

Degree of f(x) at denominator = 1

So, one oblique asymtote form.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9