The variable $x$ varies directly as the square of $y$, and $y$ varies directly as the cube of $z$. If $x$ equals $-16$ when $z$ equals 2, what is the value of $x$ when $z$ equals $\frac{1}{2}$?

If varies directly as , then there is some constant for which

Similarly, there is some constant such that

Given that when , we have

Now when , we get

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

m a t h w a y. c o m

step-by-step explanation: