A grocer wants to mix two kinds of candy. One kind sells for $1.10 $ ⁢ 1.10 per pound, and the other sells for $2.55 $ ⁢ 2.55 per pound. He wants to mix a total of 28 28 pounds and sell it for $1.25 $ ⁢ 1.25 per pound. How many pounds of each kind should he use in the new mix? (Round off the answers to the nearest hundredth.)

1st candy: 19.83 pounds,

2nd candy: 5.17 pounds.

Step-by-step explanation:

Let x represent pounds of 1st candy and y represent pounds of 2nd candy.

We have been given that grocer wants to mix a total of 28 pounds. We can represent this information in an equation as:

We are also told that one kind sells for $1.10 per pound, and the other sells for $2.55 per pound. He wants to mix a total of 28 pounds and sell it for $1.25 per pound. We can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:

Therefore, the grocer should mix approximately 19.83 pounds of 1st candy.

Now, we will substitute in equation (1) to solve for y as:

Therefore, the grocer should mix approximately 5.17 pounds of 2nd candy.

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: