Y=×^2+4×-5 what is the axis of symmetry??

x = -2

Step-by-step explanation:

Given a generic equation,

y = ax² + bx + c

the axis of symmetry is given by (-1/2)(b/a)

In this problem, you're given

y = x² + 4x -5

y = 1x² + 4x + -5

y = ax² + bx + c

you're b=4, a=1

so your axis of symmetry is:

x = (-1/2)(b/a)

x = (-1/2)(4/1)

x = -2

what is the information provided?

step-by-step explanation:

1.30

step-by-step explanation: