How could I solve y= 2x^2 + 16x - 66

By using quadratic formula?

the solutions are

x = 3 or x = - 11

Step-by-step explanation:

The given quadratic equation is expressed as

y = 2x² + 16x - 66 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 2

b = 16

c = - 66

Therefore,

x = [- 16 ± √(16² - 4 × 2 × - 66)]/2 × 2

x = [- 16 ± √(256 + 528)]/4

x = [- 16 ± √784]/4

x = (- 16 + 28)/4 or x = (- 16 - 28)/4

x = 12/4 or x = - 44/4

x = 3 or x = - 11

The answer to your question is x₁ = 3  x₂ = -11

Step-by-step explanation:

Data

                    y = 2x² + 16x - 66

In the quadratic formula, we use the coefficients

a = 2

b= 16

c = -66

Formula

Substitution

x =  

Simplification

6/20

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3