Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than to B.

Given points A(3, -5) and B(19, -1), find the coordinates of point C such that CB/AC = 1/7.

1) C (9,-3.5)

2) C (17,-1.5)

Step-by-step explanation:

1)

To solve this problem, we must divide the segment AB into 8 equal intervals, and then find the point sitting at 3/8 of the whole segment.

The end points of the segment in this problem are:

and

This means that the x- and y-coordinates of point C are given by the equations:

And substituting the values of the coordinates of A and B, we find:

2)

In this problem, we want to find the coordinates of point C such that:

(1)

As before, the coordinates of the endpoints of the segment AB are:

and

We can call the coordinates of point C as follows:

To satisfy eq.(1) for the x-coordinate, we have:

Therefore, by substitution we find:

Similarly on the y-coordinate we find:

And solving we get:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?