A large shipping company wants each order to arrive within the delivery window they give to the customer. They plan on taking a random sample of orders to construct a one-sample z interval to estimate what proportion of all orders arrive within their delivery window. They'll use a confidence level of 95%, percent, and they don't want the margin of error to exceed 2 percentage points. Previous data suggests that about 90%, percent of orders arrive within their delivery window. If we assume that p=0.90, what is the smallest sample size required to obtain the desired margin of error?

The smallest sample size required to obtain the desired margin of error is 865.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

95% confidence level

So , z is the value of Z that has a pvalue of , so .

If we assume that p=0.90, what is the smallest sample size required to obtain the desired margin of error?

The margin is n when . So

The smallest sample size required to obtain the desired margin of error is 865.

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions