Red 11 pencils in a box blue 11 green 3 the original 25 colored pencils have all been placed back in the box and another 11 colored pencils were added to the box. The pencils are either red, blue or green. The likelihood of drawing a green pencil is now greater than the likelihood of drawing a red pencil but less than the likelihood of drawing a blue pencil. how many pencils of each color were added to the box? Explain how you know that your answer is the only possible outcome that meets all conditions

10 green and 1 blue pencils

Step-by-step explanation:

Exactly 11 pencils were added

Blue pencils became highest, for it to be highest, it has to be more than all the other ones. So if 10 is added to the original number it will make it 13 higher than all, and the remaining one is added to green to make it 12 higher than red.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)