Lisa sold $75 worth of play tickets. Adult tickets cost $4 each and children’s ticket cost $4 each. How many children’s tickets could she have sold?Is there more than one answer

Yes, there are many possible answers. An equation that can model your situation is:
4a+4b=75, with a being the amount of adult tickets sold, and b being the amount of children’s tickets sold.
Because both tickets cost 4 dollars, you would multiply the amount of tickets sold, by the price (in dollars) of the ticket.
So, you can find possible answers by substituting the amount of adult tickets sold. Say, 4 adults bought tickets. You could then substitute a for 4. So the equation would look like this.
4(4)+4b=75
16 + 4b = 75
4b = 75 - 16
4b = 59
Divide each side by four
B = 14.75

The reason you got a decimal number is because 75 cannot be divided by 4 evenly. So, in this context, you could say that 15 children bought tickets. One child had an issue, and Lisa gave them a 25% discount. This would explain why there are only 75 dollars worth in tickets. I hope I helped, this is my first question I have ever answered so I’m not entirely sure if this was helpful or not. Hope you figure this out!

The length of what is left would be 1 1/2 feet long.