Mathematics
Mathematics, 27.02.2020 05:53, jadentdaniels

The first such distribution found is Ο€(N) ~
N
/
log(N)
, where Ο€(N) is the prime-counting function and log(N) is the natural logarithm of N. This means that for large enough N, the probability that a random integer not greater than N is prime is very close to 1 / log(N). Consequently, a random integer with at most 2n digits (for large enough n) is about half as likely to be prime as a random integer with at most n digits. For example, among the positive integers of at most 1000 digits, about one in 2300 is prime (log(101000) β‰ˆ 2302.6), whereas among positive integers of at most 2000 digits, about one in 4600 is prime (log(102000) β‰ˆ 4605.2). In other words, the average gap between consecutive prime numbers among the first N integers is roughly log(N).[1]

answer
Answers: 2

Other questions on the subject: Mathematics

image
Mathematics, 21.06.2019 16:00, diamondd4
What is the value of x in the diagram below?
Answers: 2
image
Mathematics, 21.06.2019 16:40, sandygarcia65
What is the solution of the systems of equations? y=2/3x+3 x=-2
Answers: 2
image
Mathematics, 21.06.2019 19:00, sayrieee
Ineed i been stuck on this question since yesterday
Answers: 1
image
Mathematics, 21.06.2019 20:00, bfgnnnbddf6830
How do i multiply two digit numbers
Answers: 1
Do you know the correct answer?
The first such distribution found is Ο€(N) ~
N
/
log(N)
, where Ο€(N) is the...

Questions in other subjects:

Konu
Mathematics, 21.09.2021 14:00
Konu
Mathematics, 21.09.2021 14:00
Konu
Mathematics, 21.09.2021 14:00
Konu
Mathematics, 21.09.2021 14:00
Konu
Geography, 21.09.2021 14:00