The top of a 10-ft ladder is leaning against a wall, and the base of the ladder is on the ground. If the top of the ladder slides down the wall at a rate of 2 ft/sec, how fast (in ft/sec) is the bottom of the ladder moving along the ground when the bottom of the ladder is 5 ft from the wall?

Ladder is moving away from the wall with the speed of 3.464 ft/s

Step-by-step explanation:

Consider the figure attached

Given that top of ladder slides down with the speed of 2ft/sec, i.e

Length of ladder =10 ft

bottom of the ladder is 5 ft from the wall i.e b=5

By pythagorous theorem

Differentiating equation (1) w.r.to t

Negative sign shows that ladder is moving away from wall

28

step-by-step explanation:

because that's the answer

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.