How many liters of a 20% acid solution should be added to 10 liters of a 30% acid solution to obtain a 25% acid solution?

We have 10 liters of 30% acid

We want to add "x" liters of 20% acid to make a 25% acid solution.

.30 * 10 + .20x = .25 * (10 +x)

3 + .20x = 2.5 + .25x

.5 = .05 x

x = 10 liters

CHECKING THE CALCULATIONS:

10 liters of 30% acid + 10 liters of 20% acid =

20 liters of 25% acid

Step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )